Question

One card is drawn from a well - shuffled deck of 52 cards . calculate probability that the card will
i) be an ace
ii) Not be ace

Answer 1

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There are 52 playing cards in which 4 are aces......

1.)Probability(not an ace) =
There are 52 cards in which 4 aces are there and if we will remove 4 aces we will be left with.....

So, 52 - 4 = 48
There fore,
P(not an ace) = $\frac{48}{52}$

So, If we will cut them we will left with...

P(not an ace) = $\frac{12}{13}$

2.)Probability(be an ace) =$\frac{4}{52}$

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Answer 2

Answer:

Step-by-step explanation:

(I) probability it is a ace is4/52=1/13=0.0769230.

(II) probability it is not a ace is 48/52=0.9230769