Math, asked by nishajoshi1298, 1 year ago

one card is tossed three times, find the probability that it is a king or diamond is.plz answer , plz answer​


shreyakolahal: Welcome

Answers

Answered by shreyakolahal
5

Answer:

Step-by-step explanation:

Probability: three times So obviously 2/3

Answered by Mulji
3

In a playing card there are 52 cards.

Therefore the total number of possible outcomes = 52

(i) ‘2’ of spades:

Number of favourable outcomes i.e. ‘2’ of spades is 1 out of 52 cards.

Therefore, probability of getting ‘2’ of spade

Number of favorable outcomes

P(A) = Total number of possible outcome

= 1/52

(ii) a jack

Number of favourable outcomes i.e. ‘a jack’ is 4 out of 52 cards.

Therefore, probability of getting ‘a jack’

Number of favorable outcomes

P(B) = Total number of possible outcome

= 4/52

= 1/13

(

=

Therefore, probability of getting ‘a black card’

Number of favorable outcomes

P(H) = Total number of possible outcome

= 26/52

= 1/2

(ix) a non-ace:

Number of ace cards in each of four suits namely spades, hearts, diamonds and clubs = 1

Therefore, total number of ace cards out of 52 cards = 4

Thus, total number of non-ace cards out of 52 cards = 52 - 4

= 48

Therefore, probability of getting ‘a non-ace’

Number of favorable outcomes

P(I) = Total number of possible outcome

= 48/52

= 12/13

(x) non-face card of black colour:

Cards of spades and clubs are black cards.

Number of spades = 13

Number of clubs = 13

Therefore, total number of black card out of 52 cards = 13 + 13 = 26

Number of face cards in each suits namely spades and clubs = 3 + 3 = 6

Therefore, total number of non-face card of black colour out of 52 cards = 26 - 6 = 20

Therefore, probability of getting ‘non-face card of black colour’

Number of favorable outcomes

P(J) = Total number of possible outcome

= 20/52

= 5/13

(xi) neither a spade nor a jack

Number of spades = 13

Total number of non-spades out of 52 cards = 52 - 13 = 39

Number of jack out of 52 cards = 4

Number of jack in each of three suits namely hearts, diamonds and clubs = 3

[Since, 1 jack is already included in the 13 spades so, here we will take number of jacks is 3]

Neither a spade nor a jack = 39 - 3 = 36

Therefore, probability of getting ‘neither a spade nor a jack’

Number of favorable outcomes

P(K) = Total number of possible outcome

= 36/52

= 9/13

(xii) neither a heart nor a red king

Number of hearts = 13

Total number of non-hearts out of 52 cards = 52 - 13 = 39

Therefore, spades, clubs and diamonds are the 39 cards.

Cards of hearts and diamonds are red cards.

Number of red kings in red cards = 2

Therefore, neither a heart nor a red king = 39 - 1 = 38

[Since, 1 red king is already included in the 13 hearts so, here we will take number of red kings is 1]

Therefore, probability of getting ‘neither a heart nor a red king’

Number of favorable outcomes

P(L) = Total number of possible outcome

= 38/52

= 19/26

These are the basic problems on probability with playing cards.

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