one cc of oxygen at NTP contains ___ atoms
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Since oxygen molecule is diatomic , the given sample will contain 3.0110×10 raised to 23 atoms of oxygen. 5.6l of O2 means we have 0.25 moles of O2. and as 1 molecule of O2 has 2 atoms, so, 1.50575*10^23 molecules will have 2*1.50575*10^23 atoms=3.0115*10^23 atoms of O...
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