One circle has a radius of 98 cm and a second concentric circle has a radius of 1 m 26 cm how much longer is the circumference of the second circle than that of the first
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Radius 1 = 98cm
Radius 2 = 126cm ( 1m = 100cm)
Circumfrence of circle 1 = 2*PIE*R1
→2*22/7*98
→2*22*14 ( 7 AND 98 will cancle each other)
→44*14 = 616cm
Circumfrence or circle 2 = 2*PIE*R2
→2*22/7*126
→2*22*18 ( 7 & 126 will cancle each other)
→44*18 = 792cm
Difference = C2 - C1
→792-616 = 176cm
Radius 2 = 126cm ( 1m = 100cm)
Circumfrence of circle 1 = 2*PIE*R1
→2*22/7*98
→2*22*14 ( 7 AND 98 will cancle each other)
→44*14 = 616cm
Circumfrence or circle 2 = 2*PIE*R2
→2*22/7*126
→2*22*18 ( 7 & 126 will cancle each other)
→44*18 = 792cm
Difference = C2 - C1
→792-616 = 176cm
Answered by
1
Given:-One circle has a radius of 98 cm and a second concentric circle has a radius of 1 m26 cm or 126cm
To find out:-How much longer is the circumference of the second circle than that of first?
Solution:-
Let the radius of outer circle be r1 and inner circle be r2 .
CIRCUMFERENCE of inner circle = 2πr1
=>2×22/7×98
=>616 cm
CIRCUMFERENCE of outer circle = 2πr2
=>2×22/7×126
=>792 cm
DIFFERENCE of outer circle and inner circle
=>792-616=176 cm
circumference of the second circle is 176 cm longer than that of first.
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