Question

One coin and one die are thrown simultaneously. Find the probability of the following events. Event A : To get head and a prime number. Event B : To get a head or tail and an odd number. Event C : Number on the upper face is greater than 6 and tail on the coin.​

Answer 1

$solution$

A coin is tossed and a die is thrown simultaneously.

S={H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6}

Thus n(S)=12

P is the event of getting head and an odd number.

P={H1,H3,H5}

Thus n(P)=3

Q is the event of getting either H or T and an even number.

Q={H2,H4,H6,T2,T4,T6}

Thus n(Q)=6

R is the event of getting a number greater than 7 and tail 1.

R={}

∴n(R)=0

Hence, option C is correct.

Answer 2

Answer:

$\huge \mathsf \pink{Solution}$

A coin is tossed and a die is thrown simultaneously.

S={H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6}

Thus n(S)=12

P is the event of getting head and an odd number.

P={H1,H3,H5}

Thus n(P)=3

Q is the event of getting either H or T and an even number.

Q={H2,H4,H6,T2,T4,T6}

Thus n(Q)=6

R is the event of getting a number greater than 7 and tail 1.

R={}

∴n(R)=0

Hence, option C is correct.