Question

one coulomb of electrical charge is passed through the solutions of agno3 and cuso4,connected in series,using platinum electrodes.The mass ratio ag/cu would be​

Answer 1

Answer:

The ratio of weight of $\mathrm{Ag} and \mathrm{Cu}$ deposited on Pt electrode is $107.9$ :

$31.77$

Explanation:

Step 1:

$\mathrm{Ag}^{+}+1 \mathrm{e}^{-} \rightarrow \mathrm{Ag}(\mathrm{s}) \\ \mathrm{Cu}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu}(\mathrm{s})$

According to Faraday's $11^{\text {nd }}$ law,

Ratio of the weight deposited on the electron is equal to the ratio of the equivalent weight of the substance.

Step 2:

$\frac{\mathrm{W}_{1}}{\mathrm{~W}_{2}}=\frac{\mathrm{E}_{1}}{\mathrm{E}_{2}}$

$\therefore \frac{W_{\mathrm{Ag}}}{W_{\mathrm{Cu}}}=\frac{\mathrm{E}_{\mathrm{Ag}}}{\mathrm{E}_{\mathrm{Cu}}}$

$\frac{107.9}{1} \times \frac{2}{63.54}=\frac{107.9}{31.77}$

Thus, the ratio of weight of $\mathrm{Ag} and \mathrm{Cu}$ deposited on Pt electrode is $107.9$ :

$31.77$