one cubic centimetre of iron weighs 7.8g. Write as sequences, the volumes of weight of iron cubes of sides 1cm,2cm,3cm and so on?
Answers
Step-by-step explanation:
=e
x−1
÷e
x+1
\sf \: y = {e}^{x - 1 - (x + 1)}y=e
x−1−(x+1)
\sf \: y = {e}^{x - 1 - x - 1}y=e
x−1−x−1
\sf \: y = {e}^{ - 2}y=e
−2
\sf \: y = \frac{1}{ {e}^{2} }y=
e
2
1
Final
Answer:
the Volume of the Cube are ⇒ 1,2,3...∞
∴ Weights of the Iron Cubes are ⇒ 7.2, 62.4, 210.6,....∞
Step-by-step explanation:
Given ⇒
Weight of one Iron Cube = 7.8 grams
Now,
Side of the Iron Cube = 1 cm
Volume of the Iron Cube = (1)³
= 1 cm³
Side of the Iron Cube = 2 cm
Volume of the Iron cube = (2)³
= 8 cm³
∵ 1 cm³ of Iron weighs 7.8 grams
∴ 8 cm³--------------------8 × 7.8 grams
= 62.4 grams.
Side of the Iron Cube = 3 cm
= (3)³
= 27 cm³
∵ 1 cm³ of Iron weighs 7.8 grams.
∴ 27 cm³-------------------27 × 7.8 grams
= 210 grams.
Thus, the Volume of the Cube are ⇒ 1,2,3..∞
∴ Weights of the Iron Cubes are ⇒ 7.2, 62.4, 210.6,....∞
→→→→→→→→→→
Hope it helps.
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