Question

one cubic cm of iron weight 7.8 grams write as sequence the volume of weight of iron cubes of sides 1cm ,2cm and so on

Answer 1

Hello Dear.

Here is the answer---

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Given ⇒

Weight of one Iron Cube = 7.8 grams

Now,
Side of the Iron Cube = 1 cm
Volume of the Iron Cube = (1)³
                                        = 1 cm³


Side of the Iron Cube = 2 cm
Volume of the Iron cube = (2)³
                                       = 8 cm³

∵ 1 cm³ of Iron weighs 7.8 grams
∴ 8 cm³--------------------8 × 7.8 grams
                                   = 62.4 grams.

Side of the Iron Cube = 3 cm
                                   = (3)³ 
                                   = 27 cm³

∵ 1 cm³ of Iron weighs 7.8 grams.
∴ 27 cm³-------------------27 × 7.8 grams
                                   = 210 grams.


Thus, the Volume of the Cube are ⇒ 1,2,3........∞
∴ Weights of the Iron Cubes are ⇒ 7.2, 62.4, 210.6,....∞


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Hope it helps.

HAVE A MARVELOUS DAY.

Answer 2

7.8, 62.4,210.6,499.2................

Step-by-step explanation:

Given:

One cubic cm of iron weight = 7.8 grams.

Sequence for sides of the cubes is given.

(1,2,3,4...........) cm

We get the volume weight of iron cubes by multiplying the volume of the cone with One cubic cm of iron weight.

Volume weight of iron cube = Volume of the cube $\times$ One cubic cm of iron weight

One cubic cm of iron weight = $1^{3}\times 7.8 = 1\times 7.8 = 7.8$  gm

Two cubic cm of iron weight = $2^{3}\times 7.8 = 8\times 7.8 = 62.4$ gm

Three cubic cm of iron weight = $3^{3}\times 7.8 = 27\times 7.8 = 210.6$ gm

Four cubic cm of iron weight = $4^{3}\times 7.8 = 64\times 7.8 = 499.2$ gm

Similarly and so on

Therefore, the sequence of the volume weight of iron cubes is

(7.8, 62.4,210.6,499.2................) grams