Math, asked by kottathenga12, 1 month ago

one dad after 5 years he has his age 3 times his son's but before 5 years from now he has his age 7 times than his sons so what is his age now​

Answers

Answered by abhi569
55

Answer:

Age of father is 40 year and that of son is 10 year

Step-by-step explanation: Let the present age of the son be 'x'.

          After 5 years:

Age of son = x + 5

Age of father = 3 times of x + 5

                      = 3(x + 5)

          Before 5 years,

Age of son = x - 5

Age of father = Age after 5 years - 5 - 5

                      = 3(x + 5) - 10

But in the question,  age of father is given '7 times of the son's age' i.e. 7(x - 5).

     ∴ 7(x - 5) = 3(x + 5) - 10

    ⇒ 7x - 35 = 3x + 15 - 10

    ⇒ 7x - 3x = 5 + 35

    ⇒ 4x = 40

    ⇒ x = 10

Hence the present of father is 'age after 5 years - 5' = 3(x + 5) - 5

Age of father = 3(10 + 5) - 5 = 40

Age of son = x = 10

{based on 'if your age after 5 years is 15, then your present age should be 15 - 5 = 10,   similarly, age of father after 5 years is  3(x + 5),  so his present age should be 3(x + 5) - 5. ]

Answered by Anonymous
59

Appropriate Question :-

  • After 5 years father is 3 times the age of the son and before 5 years from now father was 7 times the age of the son.

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To Find :-

  • Find the present age.

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Solution :-

Let :

{\large{\red{\rightarrowtail}}{\bf{Age  \: of  \: son = x  \: years}}}

According to Question :

Ages after 5 years :

  • Age of son = x + 5
  • Age of father = 3(x + 5)

Ages before 5 years :

  • Age of son = x - 5
  • Age of father = 3(x + 5) - 10

Solving Starts :

{\large{:{\longmapsto{\bf{7(x - 5) = 3(x + 5) -10 }}}}}

{\large{:{\longmapsto{\bf{7x - 35 = 3x + 15 - (10)}}}}}

{\large{:{\longmapsto{\bf{7x - 3x= 35 + 15 - (10)}}}}}

{\large{:{\longmapsto{\bf{7x - 3x= 35 + 5}}}}}

{\large{:{\longmapsto{\bf{4x = 40}}}}}

{\large{:{\longmapsto{\bf{x = {\cancel \frac{40}{4} }}}}}}

{\large{\purple{:{\longmapsto{\underline{\overline{\boxed{\bf{X = 10}}}}}}}}}

Therefore :

{\large{\underline{\pink{\pmb{\underline{\mathfrak{Age \:  of  \: son = x = 10 \:  years}}}}}}}

{\large{\underline{\pink{\pmb{\underline{\mathfrak{Age \:  of \:  father = 3x + 10 = 3  \times 10 + 10 = 40 years}}}}}}}

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