one dad after 5 years he has his age 3 times his son's but before 5 years from now he has his age 7 times than his sons so what is his age now
Answers
Answer:
Age of father is 40 year and that of son is 10 year
Step-by-step explanation: Let the present age of the son be 'x'.
After 5 years:
Age of son = x + 5
Age of father = 3 times of x + 5
= 3(x + 5)
Before 5 years,
Age of son = x - 5
Age of father = Age after 5 years - 5 - 5
= 3(x + 5) - 10
But in the question, age of father is given '7 times of the son's age' i.e. 7(x - 5).
∴ 7(x - 5) = 3(x + 5) - 10
⇒ 7x - 35 = 3x + 15 - 10
⇒ 7x - 3x = 5 + 35
⇒ 4x = 40
⇒ x = 10
Hence the present of father is 'age after 5 years - 5' = 3(x + 5) - 5
Age of father = 3(10 + 5) - 5 = 40
Age of son = x = 10
{based on 'if your age after 5 years is 15, then your present age should be 15 - 5 = 10, similarly, age of father after 5 years is 3(x + 5), so his present age should be 3(x + 5) - 5. ]
⇝Appropriate Question :-
- After 5 years father is 3 times the age of the son and before 5 years from now father was 7 times the age of the son.
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
⇝To Find :-
- Find the present age.
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
⇝Solution :-
❒ Let :
❒ According to Question :
✏ Ages after 5 years :
- Age of son = x + 5
- Age of father = 3(x + 5)
✏ Ages before 5 years :
- Age of son = x - 5
- Age of father = 3(x + 5) - 10
❒ Solving Starts :
❒ Therefore :
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃