Question

One day a boy walked from his house to his school at the speed of 4 km/hr and he
reached ten minutes late to the school. Next day, he ran at the speed of 8 km/hr and was
5 minutes early to the school. Find the distance between his house and school.​

Answer 1

Let the distance be x km

Difference in timing=20 min=31 hr

∴3x−4x=31

⇒4x−3x=4

⇒x=4 km

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