Question

One day a boy walks from his house to school at 4km h and he reached 10 mins late Next day he goes at the speed of 8 kmphand was 5 mins early to the school find the distance

Answer 1

Answer:

2 km

Step-by-step explanation:

let the distance be D km.

in the first case,

speed = 4km/h

so time = D/4 h, which is 10 minutes late.

in the second case,

speed = 8km/h

so time = D/8 h, which is 5 minutes earlier.

means, the difference in the times of these cases is 15 minutes or 15/60 hour = 1/4 h

so,

D/4 - D/8 = 1/4

(2D-D)/8 = 1/4

D/8 = 1/4

4D = 8

D = 2.

hence the distance is 2 km.