One day, a person went to a horse racing area. Instead of counting the number of humans an horses, he conuted 74 heads and 196 legs. How many humans and horses were there?
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Answered by
2
Hey..
Friend...
Here your solution....
Let’s say: A = Horses, and B = Humans
A + B = 75
A = 75 - B
4A + 2B = 198
4 (75 - B) + 2B = 198
300 - 4B + 2B = 198
300 - 198 = 2B
B = 102 / 2
B = 51 Humans
A = 75 - 51
A = 24 Horses
Thankyou
Friend...
Here your solution....
Let’s say: A = Horses, and B = Humans
A + B = 75
A = 75 - B
4A + 2B = 198
4 (75 - B) + 2B = 198
300 - 4B + 2B = 198
300 - 198 = 2B
B = 102 / 2
B = 51 Humans
A = 75 - 51
A = 24 Horses
Thankyou
Alexpiam:
Nice
Answered by
1
Answer:
There were 50 humans and 24 horses.
Let the number of humans be x and the. number of horses be y.
A human has one head and 2 legs and a horse has one head and 4 legs.
So, the total number of heads would be :
Number of heads of humans + Number of heads of horses = 74
→ x + y = 74.......(1)
2x + 4y = 196
→ 2(x + 2y) = 196
→ x + 2y = 98......(2)
Subtracting the value (1) from (2)
x + 2y - x - y = 98 - 74
→ y = 24.
Putting the value of y in (1)
x + y = 74
→ x = 74 - y
→ x = 74 - 24
→ x = 50.
Therefore, the number of humans (x) is 50 and the number of horses (y) is 24.
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