Math, asked by Alexpiam, 1 year ago

One day, a person went to a horse racing area. Instead of counting the number of humans an horses, he conuted 74 heads and 196 legs. How many humans and horses were there?

Answers

Answered by Swayze
2
Hey..
Friend...

Here your solution....

Let’s say: A = Horses, and B = Humans

A + B = 75

A = 75 - B

4A + 2B = 198

4 (75 - B) + 2B = 198

300 - 4B + 2B = 198

300 - 198 = 2B

B = 102 / 2

B = 51 Humans

A = 75 - 51

A = 24 Horses

Thankyou

Alexpiam: Nice
Answered by xItzKhushix
1

Answer:

There were 50 humans and 24 horses.

Let the number of humans be x and the. number of horses be y.

A human has one head and 2 legs and a horse has one head and 4 legs.

So, the total number of heads would be :

Number of heads of humans + Number of heads of horses = 74

→ x + y = 74.......(1)

\bold{The\: total\: number \:of \:legs \:would\: be:-}

2x + 4y = 196

→ 2(x + 2y) = 196

→ x + 2y = 98......(2)

Subtracting the value (1) from (2)

x + 2y - x - y = 98 - 74

→ y = 24.

Putting the value of y in (1)

x + y = 74

→ x = 74 - y

→ x = 74 - 24

→ x = 50.

Therefore, the number of humans (x) is 50 and the number of horses (y) is 24.

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