one day during their summer vacation at a beach resort, shella found twice as many sea shells as anita and anita founf five shells more than sandy. together sandy n shella found 16 sea shells. how many did each of them find
Answers
Answered by
95
Let sandy found x shells,
Then,
anita has (x+5) shells
and shella has 2(x+5) shells.
According to question,
Shells of shella + shells of sandy = 16
Therefore,
⇒2(x+5) + x =16
⇒2x+10+x=16
⇒3x=16-10
⇒x=6/3
⇒x=2
Therefore,
Shells with shella = 14
Shells with sandy = 2
Shells with anita = 7
HOPING THAT IT WILL HELP YOU!!!
Then,
anita has (x+5) shells
and shella has 2(x+5) shells.
According to question,
Shells of shella + shells of sandy = 16
Therefore,
⇒2(x+5) + x =16
⇒2x+10+x=16
⇒3x=16-10
⇒x=6/3
⇒x=2
Therefore,
Shells with shella = 14
Shells with sandy = 2
Shells with anita = 7
HOPING THAT IT WILL HELP YOU!!!
kooper:
plz mark it as the brainliest
no option fr that
by the way sorry fr the trouble i guess i hv got too much hw
k, option will be there only if there are two answers, i think
ya
Answered by
2
Answer:
lovely answer thank you so so much
Similar questions