Question

One day during their vacation at a beach resort Shilla found twice as many sea shells as shells .How many did each of them find? ​

Answer 1

Let sandy found x shells,

Then,

anita has (x+5) shells

and shella has 2(x+5) shells.

According to question,

Shells of shella + shells of sandy = 16

Therefore,

⇒2(x+5) + x =16

⇒2x+10+x=16

⇒3x=16-10

⇒x=6/3

⇒x=2

Therefore,

Shells with shella = 14

Shells with sandy = 2

Shells with anita = 7

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Answer 2

Answer:

Step-by-step explanation:

anita has (x+5) shells

and shella has 2(x+5) shells.

According to question,

Shells of shella + shells of sandy = 16

Therefore,

⇒2(x+5) + x =16

⇒2x+10+x=16

⇒3x=16-10

⇒x=6/3

⇒x=2

Therefore,

Shells with shella = 14

Shells with sandy = 2

Shells with anita = 7