Question

one day I asked the son of my close friend about his age that child replied in different ways he said one a year ago my dad was 8 times as old as me now his age in years is equal to the square of my age represent the above situation in in the form of quadratic equation and find their ages

Answer 1

Let the present age of son be x and the age of father be x2
According to the question
1 year ago
Age of son=x-1
age of father=x2 - 1
x2-1=5(x-1)
x2-1=5x-5
x2-5x-1+5=0
x2-5x+4=0
by factorisation
x2-4x-x+4=0
x(x-4)-1(x-4)=0
(x-4)(x-1)=0
If x-4=0
x=4
the present age of son is 4years
And the present age of his father is (4)2=16 years..

Answer 2

Answer:

Step-by-step explanation:

Ethan1 Virtuoso

let the present age of son be x and age of father be y

ATQ

y= 8(x-1)

y= x^2

then putting eqn 1 in 2

8x - 7 = x^2

x^2-8x+8=0

x= 4