Math, asked by manishdutt120883, 6 months ago

ONE DAY , MY MOTHER HAD KEPT CANDIES FOR ME AND MY TWO SISTERS IN A BOX AND ASKED US TO SPLIT THEM EQUALLY AMONG US. I WAS THE FIRST ONE TO REACH HOME THAT DAY. I TOOK MY SHARE AND LEFT THE OTHERS SHARES IN THE BOX FOR MY SISTERS. AFTER A WHILE, MY ELDER SISTER SIYA REACHED HOME AND THOUGHT THAT SHE WAS THE ONE TO REACH HOME . SHE TOOK HER SHARE FROM THE BOX AND LEFT TWO EQUAL SHARES FOR US .
IN THE END , MY OTHER SISTER JAYA , REACHED HOME . SHE TOO THOUGHT TO BE THE FIRST ONE TO REACH HOME . SO, SHE TOOK HER SHARE AND LEFT 8 CANDIES IN THE BOX .
IN THE EVENING , WHEN WE ALL MET, WE REALISED WHAT HAD HAPPENED . OUR MOTHER THEN DISTRIBUTED THE 8 CANDIES AMONGST US SO THAT WE ALL GET EQUAL CANDIES.

QUESTIONS TO DISCUSSION :
1. HOW DID THE MOTHER DISTRIBUTE THE 8 CANDIES ? HOW MANY DID EACH OF DEEPA , SIYA , JAYA GET?
2. HOW DID THE MOTHER TREAT HER 3 DAUGHTERS ?
3. HOW DID JAYA FEEL WHEN SHE REALISED WHAT HAD HAPPENED ?

Answers

Answered by topwriters
15

Mother gave each child 9 candies in total

Step-by-step explanation:

Let the total portion of candies in the box be = 3x candies

First Deepa takes = 3x/3 = x candies

Balance = 3x - x = 2x candies

Siya takes = 2x/3

Balance = 2x - 2x/3 = 4x/3 candies

Jay takes = 4x/3 * 1/3 = 4x/9 candies

Left candies = 8 candies

Balance = 4x/3 - 4x/9 = 8x/9

Now 8x/9 = 8 candies left in box

Therefore x = 8*9/9 = 9.

Deepa takes 9 candies.

Siya takes = 2/3(9) = 6 candies

Jaya takes = 4/9(9) = 4 candies

Total number of candies kept by mother = 3x = 27 candies.

1) Mother distributed 8 candies left as follows:

Each child should get 9 in total. Deepa already took 9, so she did not get any more. Siya got 3 more and Jaya got 5 more from their mother.

2) The mother treated all her 3 daughters equally.

3) Jaya felt bad for herself, but happy for her sisters.

Answered by bagadaharesh28
1

Answer:

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