One day, my mothers has kept Candies for
me and
my
to bisters in a box and asked
us to split them equally amoung I was
the first one to reach here that day. I took
My share and logy the other top store in the
box for my distors. After a while, my older
o sistex siya zeeches borse on po taste
was the first one to reach homexre to hez
shase from the box ons les tis equal US.
In the end, my other sistersproches home.
see too thought to be the first one to reach tone.
so, the took her share and left & candies in the bar
In the evening when we all met, we realised what
had happened. Oux mother then distributed the X
Candies amongst us so that we all get equal cance
Questions for discussion:
ya
How did the the mother distribute te 8
Candies? How mar
ang did each of deepa,
siyo and Jaya get?
Answers
Answer:
The correct answer is that the Mother gave each child 9 candies in total
Explaination:
The Mother has given 9 Candies to all the daughters.We can explain this as below
Step-by-step explanation:
Let the total portion of candies in the box be = 3x candies
First Deepa takes = 3x/3 = x candies
Balance = 3x - x = 2x candies
Siya takes = 2x/3
Balance = 2x - 2x/3 = 4x/3 candies
Jay takes = 4x/3 * 1/3 = 4x/9 candies
Left candies = 8 candies
Balance = 4x/3 - 4x/9 = 8x/9
Now 8x/9 = 8 candies left in box
Therefore x = 8*9/9 = 9.
Deepa takes 9 candies.
Siya takes = 2/3(9) = 6 candies
Jaya takes = 4/9(9) = 4 candies
Total number of candies kept by mother = 3x = 27 candies.
1) Mother distributed 8 candies left as follows:
Each child should get 9 in total. Deepa already took 9, so she did not get any more. Siya got 3 more and Jaya got 5 more from their mother.
2) The mother treated all her 3 daughters equally.
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