Question

One day prakash left home and walked 10 km towards south,turned right and walked 5 km, turned left and walked 10km.how many km will he have to walk to reach his home straight

Answer 1

He moved from A to B to C to D

 

The distance required is AD

 

DE = 5km

 

AE = 20km

 

By Pythagoras Theorem

 

AD^2 = 5^2 + 20^2

 

AD^2 = 425

 

AD = 20.6 km

Answer 2

Answer:

2.6 km

Step-by-step explanation:

Given : One day prakash left home and walked 10 km towards south,turned right and walked 5 km, turned left and walked 10km

To Find: .how many km will he have to walk to reach his home straight

Solution :

REFER THE ATTACHED FIGURE

Prakash left home and walked 10 km towards south i.e. AB = 10 km

Then turned right and walked 5 km . i.e. BC = 5 km

Then turned left and walked 10 km i.e. CD=10 km

we need to find how many km will he have to walk to reach his home straight i.e. AD

so considering the figure we can see that we need to use Pythagoras theorem

$hypotenuse^{2}=perpendicular^{2} +base^{2}$

$AD^{2}=AE^{2} +DE^{2}$

$AD^{2}=20^{2} +5^{2}$

$AD^{2}=400 +25$

$AD=\sqrt{425}$

$AD=20.6$

Thus he will walk 2.6 km to reach his home straight