Math, asked by HemanthT2284, 11 months ago

One day three friends akash aditya and manoj went to children park to play some game while playing at one moment akash is at point p aditya is at point a and manoj is at point b

Answers

Answered by amitnrw
4

The coordinates of P are  ( 5 , 4)   or ( -1 , 6)  and Aakash Distance from Aditya & Manoj  = 2√5 m

Step-by-step explanation:

Aditya   point A ( 1 , 2)

Manoj   point B  ( 3 , 8)

Aakash Distance from Aditya & Manoj are equal

Let say coordinate of P = (x , y)

=> (x - 1)² + (y -2)² = (x - 3)² + (y - 8)²

=> x² - 2x + 1 + y² -4y + 4 = x² - 6x + 9 + y² - 16y + 64

=> 4x + 12y = 68

=> x + 3y  = 17

Area of Triangle PAB  P(x , y)  A ( 1 , 2) ,  B  ( 3 , 8)

= (1/2)| x(2 - 8)  + 1 (8 - y) + 3(y - 2)|

= (1/2)| -6x + 8 - y + 3y - 6|

= (1/2) | -6x + 2y + 2|

= -3x + y + 1    or    3x - y - 1

-3x + y + 1  = 10

=> -3x + y = 9

       x + 3y  = 17

=> y = 6  , x = - 1

3x - y - 1 =  10

=> 3x- y = 11

     x + 3y  = 17

=>   x = 5  & y = 4

Aakash Distance from Aditya & Manoj  = √ (5 - 1)² + (4-2)² = √(5 - 3)² + (4 - 8)² = √20 = 2√5

or √ (-1 - 1)² + (6-2)² = √(-1 - 3)² + (6 - 8)² = √20

the coordinates of P are  ( 5 , 4)   or ( -1 , 6)

Aakash Distance from Aditya & Manoj  = √20 m

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