Math, asked by komalprincess, 10 months ago

One day when Effedac reached the shop, he found that all the apples were sold. The fruit seller was also puzzled and he told him about the sale of apple for the last three days.

On day one, he had stacked 80 apples to be sold: he sold some of the apples by evening.

On day two, he doubled the number of apples which were left. By the end of the day he sold the same number of apples as on the previous day.

On day three, the fruit seller decided to have thrice the number of apples as were left on day two. By the end of the day, all of his apples were sold. He wondered how there was no apple left, when he had sold the same number of apples the previous day and the day before that.

Answers

Answered by komal6617
4

According to the question, equation is:

= 3 { 2 ( 80 - x ) - x } - x = 0

= 6 ( 80 - x ) - 3x - x = 0

= 480 - 6x - 3x -x = 0

= 480 - 10x = 0

= 480 = 10x

= 480/10 = 48 apples sold everyday

No of apples sold on 1st day = ( 80 - x )

On day 2nd = 2 ( 80 - x ) = x

On day 3rd = 3 { 2 ( 80 - x ) - x } - x = 0

Verify -

= 2 ( 80 - 48 ) - 48 = 0

= ( 2 x 32 ) - 48

= 64 - 48 = 16

= ( 3 x 16 ) - 48

= 48 - 48 = 0

Answered by Anonymous
3

fruit seller sells apple and orange and made profit of rupee 1.5 by selling 1 apple and sell a orange at a loss of 50paise so,

total profit or loss by selling one apple and one orange = 1.5-5= 1 rupee profit

on one day he loss 76 rupee and he sell 60 apple so, 60 apples at 60*1.5 = 90 rupees

loss of 76 rupees of selling 60 apples and x orange, then

x orange = 76

x/2=76

x=152

<marquee>Ansh

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