One day you buy a packet of 100 g glucose (C6H12O6). How many C-atoms are present in the packet ?
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Answer:
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Answer: 19.87x 10^23
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Explanation:
mass of Glucose is 180g
Given mass =100g
Mass in 100g sample = 100/180 = 0.555
In 180 g no. of carbon atoms = 6 × 6.022 × 10^23
Moles of carbon present in sample = 0.55 x 6 = 3.3
In 100 g no. of carbon atoms will be= 3.3 × 6.022 ×10^23 = 19.87x 10^23
Round off then the final value will be 19.9x 10^23
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