Question

one diagonal of a rhombus is 80 m. if side of the rhombus is 50 m. then find the hight of the rhombus​

Answer 1

Answer:

Other diagonal of rhombus is 2500-1600 = 900

So 30m now height is 2 x 30 is 60m

Answer 2

Answer:

48 m

Step-by-step explanation:

Let ABCD be the given rhombus.

First step:

BD = 80 m (given)

The diagonal BD divides the Rhombus into two equal parts.

Now to find the height of the given Rhombus, we will first find the area of ∆BDC by using Heron's formula.

DC = BC = 50 m ( All sides are equal in rhombus)

Semi-perimeter = (50+50+80)÷ 2

= 90 m

Area of ∆ BCD = √90(90-50)(90-50)(90-80)

{The whole eq. is in *under root *}

=√90×40×40×10

= √1440000

=√3^2× 2^8× 5^4

= 3×2^4×5^2

=(3×16×25)m^2

=1200 m^2

We can also write that:

Area of ∆BCD = 1/2 × base × height

Therefore,

1200= 1/2 ×50 × h

1200=25h

h = 1200/25

h = 48m

Height of ∆BCD = Height of Rhombus ABCD

Thus, Height of the given Rhombus= 48m