one diagonal of a rhombus is greater than other by 4 cm if the area of rhombus is 96 CM square find the side of the Rhombus
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Area of rhombus=
\frac{1}{2} product \: of \: diagonals
96=1/2 x(x+4)
{x}^{2} + 4x - 192 = 0
(x+16)(x-12)=0.
diagonal is 12
side=36+64 root.
=10
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