Question

one diagonal of a rhombus is greater than other by 4 cm if the area of rhombus is 96 CM square find the side of the Rhombus​

Answer 1

Answer:

Step-by-step explanation:

Let one diagonal be x,

So other diagonal will be x +4

Area = 96

So x(x +4)/2 = 96

On solving x = 12 or -16(rejected as negative)

So diagonals are 12 and 16 cm in length ,

So half the diagonal = 6 and 8

Using Pythagorean theorem side of rhombus = 10 cm

Answer 2

Step-by-step explanation:

Area of rhombus=

\frac{1}{2} product \: of \: diagonals

96=1/2 x(x+4)

{x}^{2} + 4x - 192 = 0

(x+16)(x-12)=0.

diagonal is 12

side=36+64 root.

=10

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