one diagonal of a rhombus is greater than other by 4cm. if the area of the rhombus is 96cm².find the side of the rhombus
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let, first diagonal equal to x and second diagonal equal to x + 4.
area of rhombus = { half of diagonal 1× diagonal 2}
no putting the value of D1 and D2 on the formula.
then we get equations
x2 + 4x-192 =0
then we solve this equation and find x =-16,12
so ,when we use positive number 12 because length is always positive.
hence, first diagonal is 12 and second diagonal is 16.
I hope this answer is clear to you.
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