one diagonal ofa rhombus is 30cm long.If one of its side is 17 cm find the lenght of the other diagonal
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Answered by
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The diagonal bisect at right angles.
Refer the attachment for the figure
Let the other diagonal be d
=> 15² + (d/2)² = 17²
=> d²/4 = 17² - 15²
=> d²/4 = (17 + 15)(17 - 15)
=> d²/4 = (32)(2)
=> d²/4 = 64
=> (d/2)² = (8)²
=> d/2 = 8
=> d = 8 × 2
=> d = 16 cm
Refer the attachment for the figure
Let the other diagonal be d
=> 15² + (d/2)² = 17²
=> d²/4 = 17² - 15²
=> d²/4 = (17 + 15)(17 - 15)
=> d²/4 = (32)(2)
=> d²/4 = 64
=> (d/2)² = (8)²
=> d/2 = 8
=> d = 8 × 2
=> d = 16 cm
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Mankuthemonkey01:
Thank you
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Answered by
40
HEY MATE HERE IS YOUR ANSWER
We know that,
Diagonal of rhombus bisect each other.
Let other diagonal be x
➡️ 15^2 + ( d/2 )^2 = 17^2
➡️ d^2/4 = 17^2 - 15^2
➡️ d^2/4 = (17-15)(17 +15)
➡️ d^2/4 = (2)(32)
➡️ d^2/4 = 64
➡️ d/2 ^2 = 8
➡️ d/2 = 8
➡️ d = 8 × 2
➡️ d = 16
Therefore,
Another diagonal is 16 cm
We know that,
Diagonal of rhombus bisect each other.
Let other diagonal be x
➡️ 15^2 + ( d/2 )^2 = 17^2
➡️ d^2/4 = 17^2 - 15^2
➡️ d^2/4 = (17-15)(17 +15)
➡️ d^2/4 = (2)(32)
➡️ d^2/4 = 64
➡️ d/2 ^2 = 8
➡️ d/2 = 8
➡️ d = 8 × 2
➡️ d = 16
Therefore,
Another diagonal is 16 cm
excuse me xD You have assumed diagonal to be x and copy pasted mine?
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