one digit is 4 times of other digit in two digit number on adding this number to number formed by replacing its digit sum will be 110 find the number
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Answered by
9
x=4y
and nos are
10x+y
and other no is 10y+x
now 11x+11y=110
x+y=10
4y+y=10
y=2
x=4×2
=8
number is 28 or 82
and nos are
10x+y
and other no is 10y+x
now 11x+11y=110
x+y=10
4y+y=10
y=2
x=4×2
=8
number is 28 or 82
GunjanJathliya:
solve again and post it
what is the meaning of now u write on the solution
in starting line
second line
Answered by
15
Let the tens place digit be a
And unit place digit be b
According to first condition ,
b = 4a ------(1)
According to second condition,
10a + b + 10b + a = 110
=> 11a + 11b = 110
=> a + b = 10
=> a + 4a = 10 ( using equation 1)
=> 5a = 10
=> a = 2
b = 8
Required number = 28 and 82
And unit place digit be b
According to first condition ,
b = 4a ------(1)
According to second condition,
10a + b + 10b + a = 110
=> 11a + 11b = 110
=> a + b = 10
=> a + 4a = 10 ( using equation 1)
=> 5a = 10
=> a = 2
b = 8
Required number = 28 and 82
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