one digit is four times of other digit in two digit number. on adding ts number to number formed by replacing its digits ,sum will be 110 find the number .
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Let the number be 'ab'
Its expressed as 10a+b
On reversing the digits, it becomes 10b+a
Sum: 10a+b + 10b+a = 110
11(a+b) = 110
a+b = 10
Given, one digit is 4 times the other
a = 4b or b=4a [since it doesn't give any info regarding whether one's digit or 10's digit is greater]
If a = 4b
a+b = 10
5b = 10
b=2
a=8
Hence the number is either 28 or 82
Hope it helps.
Its expressed as 10a+b
On reversing the digits, it becomes 10b+a
Sum: 10a+b + 10b+a = 110
11(a+b) = 110
a+b = 10
Given, one digit is 4 times the other
a = 4b or b=4a [since it doesn't give any info regarding whether one's digit or 10's digit is greater]
If a = 4b
a+b = 10
5b = 10
b=2
a=8
Hence the number is either 28 or 82
Hope it helps.
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