Question

one digit of a two number is 3 times the digit if you want to change the digits of the two digit number and add the resulting number to the original number you got it yet what is the original number

Answer 1

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NOTE: It's not 'it yet' :-) it's 88 :-p
➖➖➖➖➖➖➖➖➖➖➖➖➖➖
✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️

Let the digit at tens place be 3x

The digit at ones place be x

Original Number = 10(3x) + x = 30x + x = 31x

Interchanged Number = 10(x) + 3x = 10x + 3x = 13x

According to Question,

31x + 13x = 88

44x = 88

x = 88 / 44

x = 2

Therefore the numbers are 13 *2 = 26

Or 31 *2 = 62

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Answer 2

Hi,

There is some question error because anything + anything = anything

So the instead of "it yet".. Tell me a number

OK lets take the number 88

It's given that

The first digit = 3 times the second digit

Therefore
Let 1st digit = x
And 2 nd digit = y

Therefore
x = 3y

Now
It's given that 10x + y + 10y + x = 88
11x + 11y =88
11(x + y) = 88
x + y = 8
3y + y = 8
4y =8
y= 2

And,
x = 3(y)
x = 3(2) = 6

So,
The 2 number = 62, 26

Bye
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