One dividing 2x³ + 6x² - (2k - 7)x + 5 by (x + 3),the remainder is k - 1 then the value of k is
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k = 3
Solution:
According the question,
f( x ) = 2x³ + 6x²- (2k - 7)x + 5 by (x + 3)
g( x ) = x + 3
Given,
Remainder = k - 1
Step-by-step explanation:
If x + 3 = 0, then x = - 3
f( - 3 ) = 2(-3)² + 6(-3)² - (2k - 7) (-3 + 5)
⟹ - 54 + 54 + 3(2k - 7) + 5
⟹ - 54 + 54 + 6k - 21 + 5
( eliminating - 54 and + 54 )
⟹ 6k - 21 + 5
⟹ 6k - 16 = k - 1
( Transposing k to L.H.S and -16 to R.H.S )
⟹ 6k - k = - 1 + 16
⟹ 5k = 15
⟹ k = 15/5
⟹ k = 3
Hence, the value of k is 3
Answered by
0
Step-by-step explanation:
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