Math, asked by Hiriyanna106, 6 months ago

One dividing 2x³ + 6x² - (2k - 7)x + 5 by (x + 3),the remainder is k - 1 then the value of k is

Answers

Answered by Ladylaurel
10

k = 3

Solution:

According the question,

f( x ) = 2x³ + 6x²- (2k - 7)x + 5 by (x + 3)

g( x ) = x + 3

Given,

Remainder = k - 1

Step-by-step explanation:

If x + 3 = 0, then x = - 3

f( - 3 ) = 2(-3)² + 6(-3)² - (2k - 7) (-3 + 5)

⟹ - 54 + 54 + 3(2k - 7) + 5

⟹ - 54 + 54 + 6k - 21 + 5

( eliminating - 54 and + 54 )

⟹ 6k - 21 + 5

⟹ 6k - 16 = k - 1

( Transposing k to L.H.S and -16 to R.H.S )

⟹ 6k - k = - 1 + 16

⟹ 5k = 15

⟹ k = 15/5

⟹ k = 3

Hence, the value of k is 3

Answered by angelpriyaomg
0

Step-by-step explanation:

hope it will help you friend

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