One electric geyser rated 1500 W, 220 V and an
electric iron rated 400 W, 220 V are connected
in parallel. Calculate the current drawn from the
main line.
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Answers
Answered by
4
P = VI
then
For geyser
I1 = 1500/220 = 6.81 A
For Electric iron
I2 = 400/220 = 1.81
Hence total charge = I = I1+I2 = 6.81+1.81
= 8.83 A
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Answered by
3
GiveN :-
◙ Power of the electric geyser = 1500 W
◙ Potential difference = 220 V
◙ Power of the electric iron = 400 W
◙ Potential difference = 220 V
TO FinD :-
The current drawn from the main line.
AcknowledgemenT :-
◙ Power(P) = Potential difference(V) × Current(I)
P = VI
◙ Potential difference(V) = Resistance(R) × Current(I)
V = IR
SolutioN :-
For the electric geyser,
1500 = 220 × I
⇒I = 1500/220
⇒I = 150/22
⇒I = 6.81 A
For the electric iron,
400 = 220 × I
⇒I = 400/220
⇒I = 40/22
⇒I = 1.81 A
∴ Total current drawn from the main line = 6.81 A + 1.81 A = 8.62 A
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