Question

one end of a 6m long adder is resting on the ground and another on the wall at 5m height from the ground. if the ladder slips down 1.5m from the wall calculate the distance by which the other end of the ladder will slip on the ground.​

Answer 1

Answer:

As wall is always perpendicular so

In the triangle by Pythagoras theorem

$(wall \: length) {}^{2} + (length \: between \: the \: wall \: \\ and \: the \: foot \: of \: ladder) \: {}^{2} =(length \: of \: ladder) {}^{2}$

$4.8 {}^{2} +( length \: between \: \: the \: \\ wall \: and \: the \: foot \: of \: the \: wall ){}^{2} = 6 {}^{2}$

$23.04+ \:( length \: between \: wall \: \\ and \: ladder) {}^{2} = 36$

$Length {}^{2} = 36 - 23.04$

$Length {}^{2} = 36 - 23.04$

$Length {}^{2} = \sqrt{} 12.96$

$Length = 3.6m$