One end of a cylindrical glass rod (μ = 1.5) of radius 1.0 cm is rounded in the shape of a hemisphere. The rod is immersed in water (μ = 4/3) and an object is placed in the water along the axis of the rod at a distance of 8.0 cm from the rounded edge. Locate the image of the object.
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Given :
Radius of cylindrical glass= R= 1cm
u= - 8cm
μ2= 3/2= 1.5
μ1= 4/3
μ2/V- μ2/u= μ2-μ1/R
3/2V + (4/3) /8 =(3/2-4/3)/1
3/2V+1/6=1/6
3/2V= 0
1/v= 0
v tends to ∞
so image is formed at infinity
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Answer is given below!
Radius of cylindrical glass= R= 1cm
u= - 8cm
μ2= 3/2= 1.5
μ1= 4/3
μ2/V- μ2/u= μ2-μ1/R
3/2V + (4/3) /8 =(3/2-4/3)/1
3/2V+1/6=1/6
3/2V= 0
1/v= 0
v tends to ∞
so image is formed at infinity
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