Question

one end of a cylindrical glass rod is ground to a hemispherical surface of radius R equal to 2 cm and object of height H not equal to 1 mm is placed on the axis of the rod you equal to 8 cm to the left of the vertex find the find the image distance v and the image height h when the rod is in air the Indices of refraction of glass and water are 1.50 and 1.33 respectively​

Answer 1

Thus the image is placed at a distance of 13.33 cm

Explanation:

We are given that:

• Radius of glass = 2 cm
• Height of object = 1 mm = 0.1 cm
• μ1 = 1.5
• μ2 = 1.33
• Distance of object = 8 cm

Solution:

- μ1 / u + μ2 / v = μ2 - μ1 / R

- 1.33 / 8 + 1.5 / v = 1.5 - 1.33 / 2

- 0.16625 + 1.5 / v = 0.2 / 2

- 0.16625 + 1.5 = 0.1 v

1.33375 / 0.1 = V

V = 13.33 cm

Thus the image is placed at a distance of 13.33 cm