one end of a diameter AB of a circle is A(3,2) and centre is C(2,2) then what is the B
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Let AB be a diameter of the circle having its centre at C(1, -3) such that the coordinates of one end A are (4, -1).
Let the coordinates of B be (x , y).
Since C is the mid-point of AB. Therefore, the coordinates of C are
(2 x+4 , 2 y−1 ).
But, the coordinates of C are given to be (1,-3).
2 x+4
=1and
2 y−1
=−3
⇒x+4=2andy−1=−6
⇒x=−2andy=−5
Hence, the coordinates of B are (-2, -5).
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