One end of a rope of mass M and length L is pulled by applying a contant horizontal force I'. Ground is rough with coellicient of friction m. It is given that (riction is insuſſicient to prevent slipping. Tension at a distance x from the end where force is applied is : F z
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Answer:
As the center of mass of the rope is at the mid point of it, the tension is equal to the Applied force−Friction force.
⇒T=F−μN=Mg−
2
1
Mg=
2
1
Mg
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Explanation:
A rope of length L and mass M is being pulled on a rough horizontal floor by a constant horizontal force F = Mg. The force is acting at one end of the rope in the same direction as the length of the rope. The coefficient of kinetic friction between rope and floor is
2
1
. Then, the tension at the mid-point of the rope is
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