Question

One end of a spring of natural length h and spring constant k is fixed at the ground and the other is fitted with a smooth ring of mass m which is allowed to slide on a horizontal rod fixed at a height h. Initially, the spring makes an angle of 37° with the vertical when the system is released from rest. The speed of the ring when the spring becomes vertical is ​ 1 2 3 4

Answer 1

cos37= h/l
l= h/cos37
l=1.25h
extension = l-h
=1.25h- h= 0.25h

equalling KE and PE
1/2mv2= 1/2k(0.25h)2
v2= k/m x h2/16 
v= h/4 √k/m

Answer 2

Answer:

Hope it helps you..............