one end of a uniform rod of mass M and length L is clamped.The rod lies on a smooth horizontal surface and rotates on it about the clamped end at a uniform angular velocity Omega. The force exerted by the clamp on the rod has a horizontal component of ??
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Horizontal component Force= Total centrifugal force acting on the rod.
Consider an element at a distance x of width dx.
dm=M/L dx
centrifugal force dF=dmv^2/x
=dmx^2w^2/x
=M/Ldx.xw^2
∴∴ Total force =
∫1-0M/Lw^2xdx
=1/2Mw^2L
Note:(1-0) is a limit of integration ok....
Hope you will understand .....
Consider an element at a distance x of width dx.
dm=M/L dx
centrifugal force dF=dmv^2/x
=dmx^2w^2/x
=M/Ldx.xw^2
∴∴ Total force =
∫1-0M/Lw^2xdx
=1/2Mw^2L
Note:(1-0) is a limit of integration ok....
Hope you will understand .....
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