Question

one end of a uniform wire of length l and mass m is attached rigidly to a point on the ceiling and a block of mass m is suspended from it lower end if area of Cross section of the wire A then stress in the wire at a distance 3l / 4 from it lower end be (1)mg/4 (2) 3mg/4 (3) 2mg /4 ( 4) 7 mg /4​

Answer 1

The tension in the string is T = 7 Mg/4

Option (4) is correct.

Explanation:

We are given

The area of Cross section of the wire  = A

Solution:

Now tension at 3L / 4 from it lower end.

Tension in the string at point 'P' is

TY = weight of load + weight of wire of length 'x'

T = mg + 3Mg/4

T = 7 Mg/4

Hence the tension in the string is T = 7 Mg/4

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A uniform rod of mass 15 kg is held stationary with the help of a light string as shown in figure Find the tension in the string.​ ?

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