One end of copper of length 1 metre and are of cross section is 10 is immersed in boiling water
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One end of a copper rod of length 1 m and cross sectional area 4.0×10−4m2 is maintained at 100∘C At the other end of the ice is kept at 0∘C.Neglecting loss of heat from surrounding the mass of ice melted in half hour is [Kcu=401w/mkandLf=3.35×105J/kg]
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Solution :
Heat generated =kAe(T2−T1)×t
=401×4×10−41(100−0)×30×60
=28800J
This heat is used up in melting ice.
28800=mL
mass of ice melted =288003.35×105
=0.086kg
=86g
Answer : 86g
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