One end of massless rope, which passes over a massless and frictionless pulley P is tied to a hook
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Area of a quadrilateral ABCD = 1/2 x AC x (Sum of the lengths of the perpendicluars on AC)
Area of the quadrilateral = 325 cm2
Length of one of the perpendicular = 14 cm
Length of AC = 25 cm
Let the length of the other perpendicular be 'x' cm
325 = 25/2 (14 + x)
650 = 25 (14 + x)
14 + x = 26
or x = 12
Area of the quadrilateral = 325 cm2
Length of one of the perpendicular = 14 cm
Length of AC = 25 cm
Let the length of the other perpendicular be 'x' cm
325 = 25/2 (14 + x)
650 = 25 (14 + x)
14 + x = 26
or x = 12
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