Question

One end of the rope is fixed to vertical wall and
other end pulled by horizontal force of 20 N. The
shape of flexible rope is shown in figure. The mass
of rope is-
SESSSSS
20 N
(A) 2 kg
(C) 3,5 kg
(B) 3 kg
(D) 4.5 kg
​

Answer 1

Answer:

where is the figure

Explanation:

without it the answer won't work and the question is incomplete

Answer 2

Answer:

The mass of the rope is (C) 3.5 kg

Explanation:

Given:

Force (F) = 20N

θ = 30°

To find:

Mass of the rope (m)

Solution:

Tsinθ = F ...(i)

Tcosθ = mg ...(ii)

Substituting the given values of θ and F in equation (i), we get

Tsinθ = F

Tsin30° = 20

T/2 = 20

T = 20×2

T = 40N

Substituting the obtained value of T and value of θ in equation (ii), we get

Tcosθ = mg

40×cos30° = mg

40×√3/2 = mg

m = (40×√3)/2g

Taking g=9.8m/s

m = 69.28/19.6

m = 3.5kg

Therefore, the mass of the rope is 3.5kg

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