Question

one end of the solid rod of length l is fixed at one end. can the magnitude and direction of torque can be estimated if the force act at endmaking an angle of 150 with horizontal​

Answer 1

Explanation:

At horizontal position the reaction 'N'.

Let the mass of rod is m.

The moment of inertia of rod about the axis passig through the end and perpendicular to its plane is

I=31ml2

For rotation of rod,

Moment of force = Applied torque

⟹x×F=Iα

⟹α=31ml2xF=ml23xF

Here α is angular acceleration about hinge .

The position of centre of mass  is aat the middle.

So the linear acceleration of centre of mass,a=α2l

a=2ml3xF

So, the net force in vertical on centre of mass is 

=ma

=2l3xF

This should be equal to N.

So, N=2l3xF