Question

One end of uniform wire of length L and of weight W is attached rigidly to a point in the roof and a weight W1 is suspended from its lower end.if s is the area of cross section of the wire,the stress in the wire at a height L/4 from its lower end is

Answer 1

Hello dear,

● Answer- (W1+3W/4)/S

● Explanation-
Net force acting at desired point is given by-
Net force = Load + 3/4th of weight of wire
F = W1 + 3W/4

Stress in the wire at given point is-
Stress = Force / Area
Stress = (W1 + 3W/4) / S

Stress in the wire will be (W1 + 3W/4) S.


Hope this helps you...

Answer 2

Answer:

Answer is( W1+W/4 ) / S

Explanation:

Formula : (Mg/A) + (Mgx/AL) = W1/S + W(L/4)/SL

Ans ;: ( W1+W/4)/S

Reason: X = the height from its lower end ( L/4 ) { X is NOT the height from its upper end !!! }