One end-point of a diameter of the sphere
2 +
2 +
2 − − 2 = 1 is (1, 1, 0). Then the other end point of diameter is ?
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Step-by-step explanation:
Let AB be the diameter of the circle center "C"
Let A (4, -1), B (x, y) and C (1, -3)
"C" is the midpoint of AB
⟹4+x2=1⟹x=−2
⟹1−y2=−3⟹y=−5
HenceB=(−2,−5)
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