Question

one equation in a system of linear equations has a slope of -3. The other equation has a slope of 4. How many solutions does the system have? Explain.

Answer 1

Answer:

(0,5)

Step-by-step explanation:

x+2y=10 and 4y-20=2x

To solve this system by substitution proceed as follows:

Solve the 1st equation for "x".

x=10-2y

Substitute that value into the 2nd equation, as follows:

4y-20=2(10-2y)

Simplify, as follows:

4y-20=20-4y

8y=40

y=5

Substitute that value into one of the equations to find a value for "x".

x=10-2(5)=0

So the solution is (0,5)

Check that answer in the other equation, as follows:

4y-20=2x

4(5)-20=2(0)

20-20=0

0=0

The solution checks.

These two lines meet at one point; the point is (0,5).