Math, asked by sp0366317, 10 months ago

one equation of a pair of depandent linear equation is -5x+7y-2=0 . the second​

Answers

Answered by abhishekmishra737007
6

Answer:

12x - 10y + 6 = 0

Step-by-step explanation:

When we multiply an equation of a straight line with a constant (not equal to zero), then this gives the dependent linear equations.

For example : ax + by + c = 0 and max + mby + mc = 0 are two dependent linear equations.

So, if one equation of a pair of dependent linear equations is 6x - 5y + 3= 0 then the second one may be 12x - 10y + 6 = 0 {Mutiplied by 2}.

Two dependent linear equations have an infinite number of solutions. (Answer)

Answered by saranshanmitha10
0

Answer:

12x - 10y+6=0

When we multiply an equation of a straight line with a constant (not equal to zero), then this gives the dependent linear equations.

For example : ax + by + c = 0 and max + mby + mc = 0 are two dependent linear equations.

So, if one equation of a pair of dependent linear equations is 6x - 5y + 3= 0 then the second one may be 12x - 10y + 6 = 0 {Mutiplied by 2}.

Two dependent linear equations have an infinite number of solutions. (Answer)

Step-by-step explanation:

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