One equation of a pair of dependent linear
equations is - 5x + 7y = 2. The second equation
can be
(1) 10x + 14y + 4 = 0
(2) - 10x - 14y + 4 = 0
(3) - 10x + 14y + 4 = 01
4) 10x - 14y = - 4
Answers
Answered by
0
Answer:
eq1:
-5x+7y=2
so 5x=7y-2
10x=14y-4
put this value in eq4
ans will be zero so equ 1 will satisfy with option 4
Answered by
0
Answer
Condition for dependent linear equationsa1a2=b1b2=c1c2=1kGive equation of line is, −5x+7y−2=0Here, a1=−5,b1=7,c1=−2From Eq. (i), −5a2=7b2=−2c2=1k [say]⇒ a2=−5k,b2=7k,c2=−2kwhere, k is any arbitrary constant.Putting k = 2, then a2=−10,b2=14and c2=−4∴ The required equation of line becomes a2x+b2y+c2=0⇒ −10x+14y−4=0⇒ 10x-14y+4=0
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