One equation of a pair of dependent linear equations is 6x - 5y + 3= 0. Find the second equation.
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3x-10y+6= 0, I think it Is correct
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12x - 10y + 6 = 0
Step-by-step explanation:
When we multiply an equation of a straight line with a constant (not equal to zero), then this gives the dependent linear equations.
For example : ax + by + c = 0 and max + mby + mc = 0 are two dependent linear equations.
So, if one equation of a pair of dependent linear equations is 6x - 5y + 3= 0 then the second one may be 12x - 10y + 6 = 0 {Mutiplied by 2}.
Two dependent linear equations have an infinite number of solutions. (Answer)
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