One exterior angle of a triangle is (10x - 16)০ and two interior opposite angles are (3x + 20)০ & (4x)০. Find the value of x.
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Using the theorem that if the side of a triangle is produced then the interior angle is equal to the sum of two interior opposite angles of the triangle.
Let ΔABC be a triangle where the side BC is produced.
By the theorem we have
∠A+∠B=100o …………..(1)
It is given that the interior opposite angles are equal i.e., ∠A=∠B.
∴ Equation (1) becomes
2∠A=100o
⇒∠A=50o
⇒∠B=50o
Using angle sum property of a triangle,
Sum of all angles of a triangle =180o
⇒∠A+∠B+∠C=180o
⇒100+∠C=180o [from (1)]
⇒∠C=180o−100o
⇒∠C=80o.
Hence ∠A=50o
∠B=50o
∠C=80o.
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